Identify Scroll bar

Thanks Virendra for sharing the answer!!

Scroll Bar is getting handle by using offset method but still its getting an error i.e.
Exception in thread “main” org.openqa.selenium.interactions.MoveTargetOutOfBoundsException: Offset within element cannot be scrolled into view: (0, 42.5): [object XrayWrapper [object HTMLDivElement]]
Command duration or timeout: 10 milliseconds

few time it successfully gets executed

Could you provide the solution for it ?

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9 Answer(s)

Hi Ravi,

Please share some code for that you have written on this?

It seems that you are asking the scroll bar to move beyond the capacity of the browser view.


Virender Singh Professor Answered on April 23, 2015.
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Hi Virendra,

Following is the script using in the Framework :

WebElement draggablePartOfScrollbar =  wd.findElement(By.xpath(“//div[@class=’fx-scrollbar-handle’]”));
System.out.println(“identified Scroll Bar”);
int x = draggablePartOfScrollbar1.getLocation().getX();
int y = draggablePartOfScrollbar1.getLocation().getY();

dragger.moveToElement(draggablePartOfScrollbar).clickAndHold(draggablePartOfScrollbar1).moveByOffset(0, y+260).release().perform();

//dragger.moveToElement(draggablePartOfScrollbar).clickAndHold(draggablePartOfScrollbar1).moveByOffset(y, y+260).release().perform();

Requirements :

This is a Vertical Scroll Bar when we move to mouse pointer to its division it gets displayed and we need to identify it and scroll  it down
If there is an alternative solution to perform this operation, Please let me know.

raviiichauhan85 Train Answered on April 23, 2015.
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Let me give a quick answer without code and will update thread with some code if required

1. So may want to use movetoelement command first to put mouse focus on the element, so that it appears.
2. Then it seems that the y axis that you are using is to big to move the element. This’ might throw the exception mentioned above.
Try smaller values of y


Virender Singh Professor Answered on April 24, 2015.
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It would be really helpful if you can share the site which has this scroll element. It seems that its not the browser scroller. Its some scroller on the HTML.

Virender Singh Professor Answered on April 24, 2015.
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That`s correct Virender,

Its not browser scroller. The website has vertical menu list and the scroll bar is hidden when the mouse moves to the vertical menu the scroll bar gets showed and we need to catch and scroll it down.

raviiichauhan85 Train Answered on April 24, 2015.
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that is Microsoft Azure Platform i need to pass the credentials to perform this action so could you come over team viewer when you feel free to come.

raviiichauhan85 Train Answered on April 24, 2015.
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Yes Ravi can do this, drop me an email at and we can take a look.

Also a screenshot and an html of the control will help too.


Virender Singh Professor Answered on April 27, 2015.
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Hi Ravi,
There is one more better way to scroll a list or any specific element on screen.

using  >>> org.openqa.selenium.internal.Locatable and
>>> org.openqa.selenium.interactions.internal.Coordinates

Try below code

import org.openqa.selenium.By;

import org.openqa.selenium.WebDriver;

import org.openqa.selenium.WebElement;

import org.openqa.selenium.interactions.internal.Coordinates;

import org.openqa.selenium.internal.Locatable;



import org.testng.annotations.Test;

public class ajaxListScroll {

public void ajaxListScrollTest() throws InterruptedException{
// Instantiate driver with browser instance


WebDriverWait wait = new WebDriverWait(driver, 70);


String findScroll = driver.findElement(By.xpath("//div[2][@class='ob_iLboICFCM']/div/span")).getText();

//System.out.println("BFP noOfScroll :: " + findScroll);

String array[] = findScroll.split(" ");

//for (int i=0;i<array.length;i++){

// System.out.println("findScroll split :: " + i + " " + array[i]);


array[5] = array[5].replace(".","");

int totalElementtoScroll = Integer.parseInt(array[5]);

//System.out.println("totalElementtoScroll :: " + totalElementtoScroll);
String array2[] = null;

int noOFElementonPageLoad=0;
for (int i=0;i<array.length;i++){

if (array[i].contains("-"))

array2 = array[i].split("-");


noOFElementonPageLoad = Integer.parseInt(array2[1]);

//System.out.println("noOFElementonPageLoad :: " + noOFElementonPageLoad);

int noOfTimetoScroll = totalElementtoScroll/noOFElementonPageLoad;

//System.out.println("noOfTimetoScroll :: " + noOfTimetoScroll);
for (int j=0; j<noOfTimetoScroll; j++){

String xpath = "//ul[@class='ob_iLboICBC']/li[" + noOFElementonPageLoad + "]/b";

//System.out.println("xpath passed :: " + xpath);


WebElement oggy = driver.findElement(By.xpath(xpath));

//System.out.println("oggy.getText() :: " + oggy.getText());

noOFElementonPageLoad += 25;

//System.out.println("noOFElementonPageLoad*2 :: " + noOFElementonPageLoad);


Coordinates coordinate = ((Locatable)oggy).getCoordinates();


System.out.println("Total Countries " + " :" + totalElementtoScroll);
for(int k=1;k<totalElementtoScroll+1;k++){

String printXpath = "//ul[@class='ob_iLboICBC']/li[" + k + "]/b";

//System.out.println("printXpath"+ printXpath);

System.out.println("Country " + k +" :"+ driver.findElement(By.xpath(printXpath)).getText());




amitjain Supporter Answered on July 1, 2015.
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You can use something like that for scrolling up/down.Just specifying the coordinates

JavascriptExecutor jse=(JavascriptExecutor)driver;

mohamedz Default Answered on September 4, 2016.
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